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A missile is fired from a jet flying horizontally at Mach 2 (2200 ft/s). The missile has a horizontal acceleration of 1000 ft/s2. Calculate its horizontal velocity at 10.0 seconds after it is fired. (Assume constant acceleration of the missile throughout its flight.) 12,200 ft/s 10,000 ft/s 2300 ft/s 7800 ft/s

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lucic

Answer:

12200 ft/s

Explanation:

The question is on constant acceleration

→Uniform acceleration motion is given by⇒⇒⇒     Vf=Vo+ at..............(a)

→Where Vf= final velocity=?

            Vo=initial velocity =2200 ft/s

              a= acceleration= 1000ft/s²

               t= 10.0 sec

Substitute values in (a) above

Vf=Vo+ at

Vf= 2200 + ( 1000×10) = 12200 ft/s

alanasessions1111

Answer:

12,200

Explanation:

got it right on odessyware

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