Answer:
The voltage will quadruple
Explanation:
The power dissipated in a circuit is given by
[tex]P=\frac{V^2}{R}[/tex]
where
V is the voltage
R is the resistance
In this problem, the voltage across the circuit is doubled:
V' = 2V
So the new power dissipated is
[tex]P'=\frac{V'^2}{R}=\frac{(2V)^2}{R}=4\frac{V^2}{R}=4 P[/tex]
so, the power dissipated will quadruple.
