Answer: 450 Bq
Explanation:
This problem can be solved using the Radioactive Half Life Formula:
[tex]A=A_{o}.2^{\frac{-t}{h}}[/tex] (1)
Where:
[tex]A[/tex] is the final amount of radioisotope (decay rate)
[tex]A_{o}=7200Bq[/tex] is the initial amount of the radioisotope
[tex]t=22min[/tex] is the time elapsed
[tex]h=5.50min[/tex] is the half life of the radioisotope
Knowing this, let's find [tex]A[/tex] from (1):
[tex]A=(7200Bq).2^{\frac{-22min}{5.50min}}[/tex] (2)
[tex]A=(7200Bq).2^{(-4)}[/tex]
[tex]A=(7200Bq)(0.0625)[/tex] (3)
Finally:
[tex]A=450 Bq[/tex]>>> This is the decay rate of the radioisotope
Note it is in Becquerels (Bq), which is the derived unit approved by the International System of Units for radioactivity
