NEED ASAP

A person walks for 100 yards then turns through an angle of 60° and walks another hundred yards. How far is she from her starting point?

Please help!! I’m not sure what formula to use!!

Respuesta :

Answer:

[tex]100\ yd[/tex]

Step-by-step explanation:

we know that

Applying the law of cosines

[tex]c^{2} =a^{2}+b^{2}-2(a)(b)cos(C)[/tex]

In this problem we have

c-----> is the distance from her starting point

[tex]a=100\ yd[/tex]

[tex]b=100\ yd[/tex]

[tex]C=60\°[/tex]

substitute

[tex]c^{2} =100^{2}+100^{2}-2(100)(100)cos(60\°)[/tex]

[tex]c^{2} =10,000+10,000-10,000[/tex]

[tex]c^{2} =10,000[/tex]

[tex]c=100\ yd[/tex]