Answer:
[tex]g^2+ 3g -10=(x-2)(x+5)[/tex]
Step-by-step explanation:
The trinomial is the following
[tex]g^2+ 3g -10[/tex]
Look for two numbers b and d that when multiplying them get as a result -10 and when you add up these numbers you get 3 as a result.
This is.
[tex]b * d = -10\\\\b + d = 3[/tex]
Then you can write the trinomial as the product of two factors:
[tex](x+b)(x+d)[/tex]
You can check that the numbers that meet this condition are:
[tex]b = -2\\d = 5[/tex]
Then the trinomial is written as
[tex]g^2+ 3g -10=(x-2)(x+5)[/tex]
