marta is solving the equation s=2πrh+2πr^2 for h. which should be the result?

s/2πr-r=h

s-r/2πr=h

s-r/2π=h

s-2π/r=h

Question

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Respuesta :

luisejr77 luisejr77 · Answer 1 · 2019-05-22T01:54:46+02:00

Answer: First option.

Step-by-step explanation:

Marta needs to subtract [tex]2\pi r^2[/tex] from both sides of the equation:

[tex]s=2\pi rh+2\pi r^2[/tex]

[tex]s- 2\pi r^2=2\pi rh+2\pi r^2- 2\pi r^2[/tex]

[tex]s- 2\pi r^2=2\pi rh[/tex]

Now she needs to divide both sides of the equation by [tex]2\pi r[/tex], then:

[tex]h=\frac{s- 2\pi r^2}{2\pi r}[/tex]

Rewriting:

[tex]h=\frac{s}{2\pi r}-\frac{2\pi r^2}{2\pi r}[/tex]

Simplifying, she should get:

[tex]h=\frac{s}{2\pi r}-r[/tex]

This matches with the first option.

lublana lublana · Answer 2 · 2019-05-22T01:57:18+02:00

Answer:

[tex]\frac{s}{2\pi r}-r=h[/tex]

Step-by-step explanation:

Given equation is [tex]s=2\pi rh+2\pi r^2[/tex].

Now we need to solve this equation for "h" and match with the given choices to find the correct choice.

[tex]s=2\pi rh+2\pi r^2[/tex]

[tex]s-2\pi r^2=2\pi rh[/tex]

[tex]2\pi rh=s-2\pi r^2[/tex]

[tex]h=\frac{s-2\pi r^2}{2\pi r}[/tex]

[tex]h=\frac{s}{2\pi r}-\frac{2\pi r^2}{2\pi r}[/tex]

[tex]h=\frac{s}{2\pi r}-r[/tex]

[tex]\frac{s}{2\pi r}-r=h[/tex]

Hence first choice [tex]\frac{s}{2\pi r}-r=h[/tex] is correct choice.