Answer:
30th percentile:109
90th percentile: 188
Step-by-step explanation:
The given data set is:
129, 113, 200, 100, 105, 132, 100, 176, 146, 152
We arrange the data set in ascending order to obtain;
Array= [tex]100,100,105,113,129,132,146,176,200[/tex]
The 30th percentile is located at
[tex](\frac{30}{100}\times 10 )}[/tex] -th position, where n=10 is the number of items in the data set
This implies that the 30th percentile is at the 3rd position.
Since 3 is an integer, the 30th percentile is the average of the 3rd and 4th occurrence in the array;
This implies that the 30th percentile = [tex]\frac{105+113}{2}=\frac{218}{2}=109[/tex]
The 90th percentile is located at
[tex](\frac{90}{100}\times 10 )}[/tex] -th position, where n=10 is the number of items in the data set
This implies that the 90th percentile is at the 9th position.
Since 9 is an integer, the 90th percentile is the average of the 9th and 10th occurrence in the array;
This implies that the 90th percentile = [tex]\frac{176+200}{2}=\frac{376}{2}=188[/tex]
