Answer:
Check attached graph
Step-by-step explanation:
Given equation of the parabola is [tex]y=-2x^2+12x-14[/tex].
Nowe we need to use the parabola tool to graph the quadratic function. Graph the parabola by first plotting its vertex and then plotting a second point on the parabola.
Compare Given equation with [tex]y=ax^2+bx+c[/tex] we get: a=-2 and b=12
then x-coordinate of vertex [tex]=x=-\frac{b}{2a}=-\frac{12}{2\left(-2\right)}=3[/tex]
plug x=3 into given function
[tex]y=-2x^2+12x-14[/tex]
[tex]y=-2(3)^2+12(3)-14=4[/tex]
Hence vertex is (3,4).
Plug any x-value say x=0 into given function to find other point
[tex]y=-2(2)^2+12(2)-14=2[/tex]
Hence second point is (2,2)
now graph the parabola using both points as shown below:
