Respuesta :
Answer:
The first pump can do 1/0 of the work per hour
Together they do 1/6 of the work per hour
The second alone would do (1/6 - 1/10) of the work per hour.
1/6 - 1/10 = 1/15
The second pump would take 15 hours to do the work.
C) 15
Hope this helps. :)
Answer:
The second pump can fill a tank with oil in 15 hours.
Step-by-step explanation:
It is given that one pump can fill a tank with oil in 10 hours. Together with a second pump, it can fill the tank in 6 hours.
Let the second pump can fill a tank with oil in t hours.
One hour work of first pump is [tex]\frac{1}{10}[/tex].
One hour work of second pump is [tex]\frac{1}{t}[/tex].
One hour work of both pump together is [tex]\frac{1}{6}[/tex].
1 hour work of both = 1 hour work of 1st pump + 1 hour work of 2nd pump
[tex]\frac{1}{6}=\frac{1}{10}+\frac{1}{t}[/tex]
[tex]\frac{1}{6}=\frac{t+10}{10t}[/tex]
Cross multiply.
[tex]10t=6(t+10)[/tex]
[tex]10t=6t+60[/tex]
Subtract 6t from both the sides.
[tex]10t-6t=60[/tex]
[tex]4t=60[/tex]
Divide both the sides by 4.
[tex]t=15[/tex]
Therefore the second pump can fill a tank with oil in 15 hours.
