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A jeweler needs 50 ounces of a 21% silver alloy. Find the amount of a 12% silver alloy and the amount of a 24% silver alloy he should mix. Solve using a system of equation.


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sqdancefan

Answer:

  • 12.5 ounces of 12% alloy
  • 37.5 ounces of 24% alloy

Step-by-step explanation:

Let x represent the amount (in ounces) of 24% alloy in the mix. Then the amount of 12% alloy is (50 -x). The amount of silver in the mix is ...

  24%·x + 12%·(50 -x) = 21%·50

  12x = 450 . . . . . . simplify, multiply by 100 (to eliminate %), and subtract 600

  x = 37.5 . . . . . . . divide by 12

The jeweler needs to mix 37.5 ounces of 24% silver alloy with 12.5 ounces of 12% silver alloy to make 50 ounces of 21% silver alloy.

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