Answer:
a = -8
b = -2
Step-by-step explanation:
We have been given the following radical expression;
[tex]\sqrt[3]{x^{10} }[/tex]
The radical can be expressed using the law of exponents;
[tex]\sqrt[n]{x}=x^{\frac{1}{n} }[/tex]
The radical can thus be re-written as;
[tex]\sqrt[3]{x^{10} }=(x^{10})^{\frac{1}{3} }[/tex]
Using the law of exponents;
[tex](a^{b})^{c}=a^{bc}[/tex]
The last expression becomes;
[tex](x^{10})^{\frac{1}{3} }=x^{\frac{10}{3} }=x^{3}*x^{\frac{1}{3} }\\\\=x^{3}\sqrt[3]{x}[/tex]
substituting x with -2 yields;
[tex]-2^{3}\sqrt[3]{-2}=-8\sqrt[3]{-2}[/tex]
