Which function has the same range as

When multiplying the function by a negative coefficient [tex]-\frac{5}{7}[/tex], now all the values of g(x) will be negative and the range of [tex]g(x)=-\frac{5}{7}(\frac{3}{5})^x[/tex] will be: (-∞, 0)

Then we must search among the options a function with range (-∞, 0)

Since the exponential functions of the form [tex](a) ^ x[/tex], where [tex]a>0[/tex] always have range (0, ∞) Then the correct option will be the one with a negative coefficient.

The correct option is the second option

xero099 xero099 · Answer 2 · 2022-03-28T19:54:28+02:00

The function [tex]h(x) = -\frac{5}{7}\cdot \left(\frac{3}{5} \right)^{-x}[/tex]same range of [tex]f(x) = - \frac{5}{7}\cdot \left(\frac{3}{5} \right)^{x}[/tex].

How to determine the range of another function based on transformations

In this question we must determine a second function whose range is equal to the range of the first one. In geometry, a rigid transformation is a transformation experimented by a function such that euclidean distance is conserved. The range is the set of values of [tex]h(x)[/tex] associated to the function.

If we apply a reflection around the y-axis, then the range is conserved but relationship between the range and the domain is changed in rigid manner. The reflection around the y-axis follows the following formula:

[tex]h(x) = f(-x)[/tex] (1)

If we know that [tex]f(x) = - \frac{5}{7}\cdot \left(\frac{3}{5} \right)^{x}[/tex], then the resulting function is:

[tex]h(x) = -\frac{5}{7}\cdot \left(\frac{3}{5} \right)^{-x}[/tex]

The function [tex]h(x) = -\frac{5}{7}\cdot \left(\frac{3}{5} \right)^{-x}[/tex] has the same range of [tex]f(x) = - \frac{5}{7}\cdot \left(\frac{3}{5} \right)^{x}[/tex]. [tex]\blacksquare[/tex]

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