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Which is the equation of the line that passes through (6, 2) and is perpendicular to a line with slope -1/3?

A. y-6=-1/3(x-2)
B. y-2=1/3(x-6)
C. y-2=3(x-6)
D. y-6=-3(x-2)
E. y-2=-3(x-6)

Which is the equation of the line that passes through 6 2 and is perpendicular to a line with slope 13 A y613x2 B y213x6 C y23x6 D y63x2 E y23x6 class=

Respuesta :

ponton

Answer:

C

Step-by-step explanation:

[tex] \frac{ - 1}{3} \times a = -1[/tex]

then

[tex]a = 3 \: where \: a \: is \: our \: line \: slope[/tex]

znk

Answer:

[tex]\boxed{\text{C. } y - 2 = 3(x - 6)}[/tex]

Step-by-step explanation:

The slope of the perpendicular line m₂ must  be the negative reciprocal of the slope m₁ of the first line.

[tex]m_{2} = -\dfrac{1}{m_{1}} = -\dfrac{1}{-\frac{1}{3}} = 3[/tex]

The only equation with m = 3 is  

[tex]\boxed{\textbf{C. } y - 2 = 3(x - 6)}[/tex]

This is the point slope form of the equation for a straight line through (6, 2) with slope = 3.

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