Respuesta :

absor201

Answer:

{x while x ≠2, -2}

Step-by-step explanation:

First let's define domain,

Domain is the set of all values on which the function is defined i.e. the function doesn't approach to infinity.

Given function is:

[tex]y = \frac{2x-4}{x^{2} -4}[/tex]

We will look for all the values of x on which the function will become undefined:

We can see that x= 2 and x=-2 will make the denominator zero as there is x^2 involved. The denominator zero will make the function undefined.

So, the domain of the function is set of all real numbers except 2 nd -2 {x while x ≠2, -2} ..

kudzordzifrancis

Answer:

[tex](-\infty,-2)\cup (-2,2)\cup (2,+\infty)[/tex]

Step-by-step explanation:

The given rational expression is:

[tex]y=\frac{2x-4}{x^2-4}[/tex]

We factor this expression to obtain:

[tex]y=\frac{2(x-2)}{(x-2)(x+2)}[/tex]

We can see that, this rational function has a hole at x=2 and a vertical asymptote at x=-2

Therefore the domain is

[tex]x\ne 2\: and\:x\ne -2[/tex]

Or

[tex](-\infty,-2)\cup (-2,2)\cup (2,+\infty)[/tex]