The population of fish in a certain lake follows the logistic growth function , where t is the time in years.


When will the population reach 20,000?

The population of fish in a certain lake follows the logistic growth function where t is the time in years When will the population reach 20000 class=

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Answer:

46 years

Step-by-step explanation:

We have the logistic growth function [tex]f(t)=\frac{25,000}{1+8.25e^{-0.076t}}[/tex]  and we want to find the time when the population will reach 20,000, to do it we just need to replace [tex]f(x)[/tex] with 20,000 and solve for [tex]t[/tex]:

[tex]f(t)=\frac{25,000}{1+8.25e^{-0.076t}}[/tex]

[tex]20,000=\frac{25,000}{1+8.25e^{-0.076t}}[/tex]

Divide both sides by 25,000

[tex]\frac{20,000}{25,000} =\frac{1}{1+8.25e^{-0.076t}}[/tex]

[tex]0.8=\frac{1}{1+8.25e^{-0.076t}}[/tex]

Multiply both sides by [tex]1+8.25e^{-0.076t}[/tex] and divide  them by 0.8

[tex]1+8.25e^{-0.076t}=1.25[/tex]

Subtract 1 from both sides

[tex]8.25e^{-0.076t}=0.25[/tex]

Divide both sides by 8.25

[tex]e^{-0.076t}=\frac{0.25}{8.25}[/tex]

[tex]e^{-0.076t}=\frac{1}{33}[/tex]

Take natural logarithm to both sides

[tex]ln(e^{-0.076t})=ln(\frac{1}{33} )[/tex]

[tex]-0.076t=ln(\frac{1}{33} )[/tex]

Divide both sides by -0.076

[tex]t=\frac{ln(\frac{1}{33} )}{-0.076}[/tex]

[tex]t[/tex] ≈ 46

We can conclude that the population will reach 20,000 after 46 years.