460 miles to San Diego
460/6=76.6 repeating -12 then divided by 2
means the other slower car was going approx 32.3 MPH
I may be wrong considering i had to google how far san diego was, if there was a graph or anything telling distance lmk
Answer:
Speed of the faster car is 68 mph and speed of slower car is 40 mph.
Step-by-step explanation:
Let the faster car has the speed = x mph
and slower car has the speed = y mph
Let the distance between San Jose and San Diago = d miles
Now we will form the first equation.
"Speed of the faster car was 12 mph less than twice the speed of the slower one"
x = 2y -12 ----------(1)
Since "faster car cover the distance d in 6 hours"
so, [tex]x=\frac{d}{6}[/tex]
"By that time the slower car still was 168 miles away from the destination"
so, [tex]y=\frac{d-168}{6}[/tex]
[tex]y=\frac{d}{6}-\frac{168}{6}[/tex]
y = x - 28 {since [tex]x=\frac{d}{6}[/tex]} ---------(2)
By substitution method,
x = 2(x - 28) - 12
x = 2x - 56 - 12
x - 2x = - 68
x = 68 mph
By putting x = 68 in equation 2
y = 68 - 28
y = 40 mph
Therefore, speed of the faster car is 68 mph and speed of slower car is 40 mph
