QUESTION 1
We want to solve the linear equation,
–12 + 3b – 1 = –5 – b
Group similar terms:
3b+b=-5+1+12
Combine similar terms,
4b=8
Divide both sides by 4
b=2.
QUESTION 2
We want to find the equation of the given line that passes through
(-3,2) and (2,-1)
The slope of this line is
[tex]m = \frac{ - 1 - 2}{2 - - 3} = - \frac{3}{5} [/tex]
The equation is given by the formula:
[tex]y-y_1=m(x-x_1).[/tex]
We plug in the known values to obtain;
[tex]y + 1= - \frac{3}{5} (x- 2)[/tex]
[tex]y + 1= - \frac{3}{5} (x - 2)[/tex]
[tex]5y + 5 = - 3x + 6[/tex]
[tex]3x + 5y = 1[/tex]
