A positive charge of +0.300 c moves horizontally due +x at speed of 250 m/s. It entered a magnetic field direction of -y with a magnitude of 0.400 T. What is the magnitude and direction of the force on the charge?

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Explanation:

The magnitude and direction of the force on the charge will be 30 N towards the +x direction.

What is Lorentz force?

Lorentz's force is defined as the force acting on a point charge when it is moving in an electric and magnetic field. Under the electric and magnetic field, a force is to act on the charge, known as the Lorentz force.

The given data in the problem is ;

q is the value of charge =  +0.300 c

B is the magnetic field strength = 0.400 T.

v is the velocity of moving charge = 250 m/s.

Mathematically, the Lorentz force is given by;

[tex]\rm F=qvB \\\\ F= 0.300 \times 250 \times 0.400 \\\\ F= 30 \ N[/tex]

Hence, the magnitude and direction of the force on the charge will be 30 N towards the +x direction.

To learn more about the Lorentz force, refer to the link;

https://brainly.com/question/13791875

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