The answers are:
[tex]x=15\\y=-10[/tex]
Solving systems of equations using elimination means multiplying/dividing the factors of the given equations in order to reduce variables and make the isolating process simpler, so, solving we have:
We are given the equations:
[tex]\left \{ {{-9x-2y=-115} \atop {-6x+2y=-110}} \right.[/tex]
We have that the terms that contains the variable "y" are equal with opposite signs, so, we can eliminate both directly, and then, isolate the variable "x", so, solving we have:
[tex]\left \{ {{-9x-2y=-115} \atop {-6x+2y=-110}} \right\\\\\left \{ {{-9x=-115} \atop {-6x=-110}} \right\\\\-9x-6x=-115-110\\\\-15x=-225\\\\x=\frac{-225}{-15}=25[/tex]
Now, that we know "x" we need to substitute it into any of the given equations in order to find "y", so, substituting we have:
[tex]-9x-2y=-115\\\\-9*(15)-2y=-115\\\\-135+115=2y\\\\2y=-20\\\\y=\frac{-20}{2}=-10[/tex]
Hence, we have that:
[tex]x=15\\y=-10[/tex]
Have a nice day!
ANSWER
(15,-10)
EXPLANATION
The given equations are:
–9x – 2y = –115 ...(1)
–6x + 2y = –110...(2)
Add equation (1) from equation (2) to eliminate y.
-9x+-6x=-110+-115
This implies that,
-15x=-225
Divide both sides by -15
[tex]x = 15[/tex]
Put the value of x into equation (2) to find y.
[tex] - 6(15 ) + 2y = - 110[/tex]
[tex] - 90+ 2y = - 110[/tex]
[tex]2y = - 110 + 90[/tex]
[tex]2y = - 20[/tex]
[tex]y = - 10[/tex]
The solution is (15,-10)
