Answer:
[tex]229.9^{\circ} C[/tex]
Explanation:
The increase in temperature of a substance is given by
[tex]\Delta T = \frac{Q}{m C_s}[/tex]
where
Q is the amount of heat absorbed by the substance
m is the mass of the substance
Cs is the specific heat capacity
In this problem,
Q = 2000.0 J
m = 10 g
Cs = 0.870 J/gC
Substituting, we find the increase in temperature:
[tex]\Delta T = \frac{2000.0 J}{(10 g)(0.870 g/JC)}=229.9^{\circ} C[/tex]
