Answer:
[tex]x = \frac32, x = -3[/tex]
Step-by-step explanation:
Hello!
We have to solve for x by using the quadratic formula.
Standard form of a quadratic: [tex]ax^2 + bx + c = 0[/tex]
Quadratic Formula: [tex]x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}[/tex]
First, convert it into standard form:
- [tex]2x^2 + 5x - 9 = 2x[/tex]
- [tex]2x^2+3x - 9 = 0[/tex]
Given our equtaion: [tex]2x^2+3x - 9 = 0[/tex]
Plug it into the formula and solve.
Solve
- [tex]x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}[/tex]
- [tex]x = \frac{-3\pm\sqrt{3^2 - 4(2)(-9)}}{2(2)}[/tex]
- [tex]x = \frac{-3\pm\sqrt{9 +72}}{4}[/tex]
- [tex]x = \frac{-3\pm\sqrt{81}}{4}[/tex]
- [tex]x = \frac{-3\pm9}{4}[/tex]
- [tex]x = \frac32, x = -3[/tex]
The roots are 1.5 and -3.
