A line passes through (1, –5) and (–3, 7). a. Write an equation for the line in point-slope form. b. Rewrite the equation in slope-intercept form. y – 5 = 3(x + 1); y = 3x + 8 y + 5 = –3(x – 1); y = –3x – 2

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ANSWER

Point-slope form:

[tex]y + 5 = -3(x - 1)[/tex]

Slope-intercept form;

[tex]y = - 3x - 2[/tex]

EXPLANATION

The point-slope form of a line is given by:

[tex]y-y_1=m(x-x_1)[/tex]

We need to find the slope using the formula:

[tex]m = \frac{y_2-y_1}{x_2-x_1} [/tex]

Let us substitute the point (1, –5) and (–3, 7).

This implies that,

[tex]m = \frac{7 - - 5}{ - 3 - 1} [/tex]

[tex]m = \frac{12}{ - 4} = - 3[/tex]

The point slope form now becomes,

[tex]y - - 5 = - 3(x - 1)[/tex]

[tex]y + 5 = -3(x - 1)[/tex]

To find the slope intercept form, we expand to obtain;

[tex]y = - 3x + 3 - 5[/tex]

[tex]y = - 3x - 2[/tex]