Answer:
The absolute vale of x in equation 2 is greater than the absolute value of x in equation 1
Step-by-step explanation:
Equation 1
|5x + 6| = 41.......................finding the absolute value of x
5x+6=41
5x=41-6
5x=35........................divide by 5 both sides
x=35/5= 7
|x|=7
Equation 2
|2x + 13| = 28........................find the absolute value of x
2x+13=28
2x=28-13
2x=15........................................divide by 2 both sides
x=15/2 =7.5
|x|=7.5
Conclusion
The absolute vale of x in equation 2 is greater than the absolute value of x in equation 1
Answer:
Solution of inequality 1:
[tex]x \in [\frac{-47}{5}, 7][/tex]
Solution of Inequality 2:
[tex]x \in [\frac{-41}{2}, \frac{15}{2}][/tex]
Step-by-step explanation:
We are given two inequalities:
Inequality 1
[tex]\mid 5x + 6 \mid = 41\\-41 \leq 5x + 6 \leq 41\\-47 \leq 5x \leq 35\\\frac{-47}{5} \leq x \leq 7\\x \in [\frac{-47}{5}, 7][/tex]
Inequality 2
[tex]\mid 2x + 13 \mid = 28\\-28 \leq 2x +13 \leq 28\\-41 \leq 2x \leq 15\\\frac{-41}{2} \leq x \leq \frac{15}{2}\\x \in [\frac{-41}{2}, \frac{15}{2}][/tex]
Solution of inequality 1:
[tex]x \in [\frac{-47}{5}, 7][/tex]
Solution of Inequality 2:
[tex]x \in [\frac{-41}{2}, \frac{15}{2}][/tex]
