Respuesta :

znk

Answer:

[tex]\boxed{\text{D. }3\sqrt{2}}[/tex]

Step-by-step explanation:

Multiply numerator and denominator by √2

[tex]\dfrac{6}{\sqrt{2}} = \dfrac{6}{\sqrt{2}} \times \dfrac{\sqrt{2}}{\sqrt{2}}\\\\= \dfrac{6\sqrt{2}}{2}\\\\= \boxed{3\sqrt{2}}[/tex]

Answer: D. [tex]3\sqrt{2}[/tex]

Step-by-step explanation:

The given fraction : [tex]\dfrac{6}{\sqrt{2}}[/tex]

Here, the denominator is in radical form which makes it not an simplified form.

So , we rationalize it by multiplying [tex]\sqrt{2}[/tex] to the numerator and the denominator , we get

[tex]\dfrac{6}{\sqrt{2}}\times\dfrac{\sqrt{2}}{\sqrt{2}=\dfrac{6\sqrt{2}}{2}}\\\\=\dfrac{2\times3\times\sqrt{2}}{2}\\\\=3\sqrt{2}[/tex]  [Cancel 2 from the numerator and the denominator.]

Hence, the choice is equivalent to the given fraction = [tex]3\sqrt{2}[/tex]

Hence, the correct option is D. [tex]3\sqrt{2}[/tex]