Write an equation to model this situation.
A1+A2=80
The formula for the area of a circle is A=πr^2. Let A1 be πr^2. If A2's r is twice A1's, then A2=π(2r)^2:
πr^2+π(2r)^2=80
*Simplify*
πr^2+π4r^2=80
*Combine like terms*
5πr^2=80
*Divide both sides by 5π*
r^2=16/π
*Take the square root of both sides*
r=4/√π
*Multiply r by 2 for the second radius*
r2=8/√π
Hope this helps!!
