In △JKL, solve for x.
(A)74.89
(B)30.29
(C)38.16
(D)66.73

ANSWER
(C)38.16
EXPLANATION
The acute angle given in the right triangle is 27°.
The side length adjacent to the 27° angle is 34 units.
The side length we want to find is x units, which is the hypotenuse of the right triangle.
We use the cosine ratio to obtain:
[tex] \cos(27 \degree) = \frac{adjacent}{hypotenuse} [/tex]
[tex]\cos(27 \degree) = \frac{34}{x} [/tex]
Solve for x,
[tex]x = \frac{34}{\cos(27 \degree)} [/tex]
[tex]x = 38.16[/tex]
to the nearest hundredth.
Answer:
The correct answer is option C. 38.16
Step-by-step explanation:
Points to remember
Trigonometric ratios
Sin θ = Opposite side/Hypotenuse
Cos θ = Adjacent side/Hypotenuse
Tan θ = Opposite side/Adjacent side
To find the value of x
From the figure we can see a right angled triangle. △JKL
Cos 27 = Adjacent side/Hypotenuse
= KL/JL
= 34/x
x = 34 / Cos 27
= 34 / 0.891
= 38.16
Therefore the correct answer is option C. 38.16