Respuesta :

r3t40

Suppose there is a function [tex]f(n)=3n^2, n\in\mathbb{N}[/tex].

We start counting by 1 from the first element in domain of natural numbers so: 1, 2, 3, 4.

We assemble the definition set [tex]A=\{1,2,3,4\}[/tex] than use the function f(n) to create transformation set:

[tex]f(A)=3\{1,2,3,4\}^2\Longrightarrow\{3,6,9,12\}^2 \\

\boxed{B=\{9,36,81,144\}}

[/tex]

So the first four terms are defined in transformation set B.

Hope this helps.

r3t40