please answer me x and my step correct please

Answer:x=4√6
Step-by-step explanation:
In ∆DCB, cos30°=BC/DB
√3/2*16=BC
BC=8√3
Applying PYTHAGORAS THEOREM in ∆BAC,
(8√3)^2=2x^2
x=4√6
Answer:
[tex]x=4\sqrt6}[/tex]
Step-by-step explanation:
Look at the picture.
ΔACD it's a triangle 30° - 60° - 90°. The sides are in ratio 1 : √3 : 2.
Therefore
CD : CB : DB = 1 : √3 : 2.
If BC = 16, then CD = 16 : 2 = 8 and CB = 8√3
ΔABC it's a triangle 45° - 45° - 90°. The sides are in ratio 1 : 1 : √2.
Therefore
AC : AB : CB = 1 : 1 : √2
If CB = 8√3, then AB = x = (8√3)/(√2)
[tex]x=\dfrac{8\sqrt3}{\sqrt2}\cdot\dfrac{\sqrt2}{\sqrt2}=\dfrac{8\sqrt6}{2}=4\sqrt6[/tex]