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Enough of a monoprotic weak acid is dissolved in water to produce a 0.0172 M solution. If the pH of the resulting solution is 2.39 at 20 °C, determine the pKa for the acid.

Respuesta :

drpelezo

Answer:

9.7 x 10⁻⁴

Explanation:

              HA     ⇄           H⁺     +        A⁻

C(eq)   0.0174             10⁻²·³⁹         10⁻²·³⁹

                              =0.0041M     =0.0041M

Ka = [H⁺][A⁻]/[HA] = (0.0014)²/(0.0174) = 9.7 x 10⁻⁴

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