Answer:
The car traveled the distance before stopping is 90 m.
Explanation:
Given that,
Mass of automobile = 2000 kg
speed = 30 m/s
Braking force = 10000 N
For, The acceleration is
Using newton's formula
[tex]F = ma[/tex]
Where, f = force
m= mass
a = acceleration
Put the value of F and m into the formula
[tex]-10000 =2000\times a[/tex]
Negative sing shows the braking force.
It shows the direction of force is opposite of the motion.
[tex]a = -\dfrac{10000}{2000}[/tex]
[tex]a=-5\ m/s^2[/tex]
For the distance,
Using third equation of motion
[tex]v^2-u^2=2as[/tex]
Where, v= final velocity
u = initial velocity
a = acceleration
s = stopping distance of car
Put the value in the equation
[tex]0-30^2=2\times(-5)\times s[/tex]
[tex]s = 90\ m[/tex]
Hence, The car traveled the distance before stopping is 90 m.
