Answer:
[tex]v = 18.4 m/s[/tex]
Explanation:
When it reached to the top of the path the normal force is given as
[tex]F_n = 370 N[/tex]
initially the reading of the sensor will give the amount of the weight of the object
[tex]W = mg = 740 N[/tex]
[tex]m = 75.4 kg[/tex]
now at the top position of the path we will have
[tex]F_n + mg = \frac{mv^2}{R}[/tex]
[tex]370 + 740 = \frac{(75.4)v^2}{23}[/tex]
[tex]1110 = 3.28 v^2[/tex]
[tex]v = 18.4 m/s[/tex]