Answer:
∠ACD≅∠CAB
Step-by-step explanation:
According to SAS postulate if two sides and the included angle of ΔDAC are same to two sides and the included angle of ΔBCA. Then ΔDAC≅ΔBCA
But for the given figure
∠DAC≅∠BCA and
CA=AC (common in both triangle)
Hence we need ∠ACD≅∠CAB to prove that ΔDAC≅ΔBCA
