Respuesta :

Answer:

Step-by-step explanation:

In this question we will find the equation of the dotted line first.

Since this line passes through two pints (0, 2) and (-3, -7)

So slope of the line will be m = [tex]\frac{y-y'}{x-x'}[/tex]

                                                 = [tex]\frac{-7-2}{-3-0}[/tex]

                                                 = [tex]\frac{-9}{-3}[/tex]

                                                 = 3

y-intercept of the line is c = 2

Now we will put these values in the standard form of the equation

y = mx + c

y = 3x + 2

Now we will check the inequality shown by shaded region

we take a point from shaded region and plug in the value of x and y.

For point ( -2, 0) y = (-2)(2)+2

                              = -4 + 2 = -2 and 0>-2

So there should be the sign of greater than.

Therefore, inequality will be y > 3x + 2

Linear inequality represented by the graph is y > 3x +2 and this can be determine by using the slope intercept form.

Given :

Two points - (0 , 2) and (-3 , -7)

Slope of the line can be calculated as follows:

[tex]m = \dfrac{y_2-y_1}{x_2-x_1}=\dfrac{-7-2}{-3-0}=3[/tex]

y intercept is 2.

Now we know that the slope intercept form is given by:

y = mx + c

y = 3x + 2 --- (1)

To check the inequality we take a point from the shaded region and plug in the value of x and y.

At Point (-3,0), equation (1) can be given by:

y = -9 + 2 = -7 < 0

Than inequality must be y > 3x + 2.

For more information, refer the link given below

https://brainly.com/question/11824567