For this case we have by definition, that the equation of a line in the slope-intersection form is given by:
[tex]y = mx + b[/tex]
Where:
m: It's the slope
b: It is the cutoff point with the y axis
To find the slope two points are needed through which the line passes:
[tex]m = \frac {y2-y1} {x2-x1}\\m = \frac {8-8} {- 5 - (- 2)} = \frac {0} {- 5 + 2} = \frac {0} {- 3} = 0[/tex]
THE equation is of the form:
[tex]y = b[/tex]
We substitute the y coordinate of the point (2,8)
[tex]8 = b[/tex]
Then, [tex]y = 8[/tex]
Answer:
[tex]y = 8[/tex]
