Starting from rest and height of 7 m, a 3kg object slides down a 30degrees incline, reaching the bottom with a speed of 10m/s . what is the work done by friction? please elaborate.

Respuesta :

Answer:

The work done by the friction is 55.8 J.

Explanation:

Given that,

Height h = 7 m

Mass of the object = 3 kg

Angle = 30°

Speed = 10 m/s

The initial potential energy of the object is converted in to the kinetic energy at the bottom of the incline and  the work done by the friction

[tex]mgh=\dfrac{1}{2}mv^2+W[/tex]

Where, m = mass of the object

v = final velocity

g = acceleration due to gravity

h = height

Put the value in the equation

[tex]3\times9.8\times7=\dfrac{1}{2}\times3\times(10)^2+W[/tex]

[tex]W = (205.8-150)\ J[/tex]

[tex]W=55.8\ J[/tex]

Hence, The work done by the friction is 55.8 J.