Respuesta :
Answer:
a = 5.05 x 10¹⁴ m/s²
Explanation:
Consider the motion along the horizontal direction
[tex]v_{x}[/tex] = velocity along the horizontal direction = 3.0 x 10⁶ m/s
t = time of travel
X = horizontal distance traveled = 11 cm = 0.11 m
Time of travel can be given as
[tex]t = \frac{X}{v_{x}}[/tex]
inserting the values
t = 0.11/(3.0 x 10⁶)
t = 3.67 x 10⁻⁸ sec
Consider the motion along the vertical direction
Y = vertical distance traveled = 34 cm = 0.34 m
a = acceleration = ?
t = time of travel = 3.67 x 10⁻⁸ sec
[tex]v_{y}[/tex] = initial velocity along the vertical direction = 0 m/s
Using the kinematics equation
Y = [tex]v_{y}[/tex] t + (0.5) a t²
0.34 = (0) (3.67 x 10⁻⁸) + (0.5) a (3.67 x 10⁻⁸)²
a = 5.05 x 10¹⁴ m/s²
The vertical acceleration provided by the deflector is 5.05 x 10¹⁴ m/s².
What is acceleration?
Acceleration can be defined as the change in speed or direction of the object or particle.
First, calculate the time for horizontal motion,
[tex]t = \dfrac d v_x[/tex]
Where,
[tex]d[/tex] - horizontal distance = 11 cm = 0.11 m
[tex]v_x[/tex] - horijontal velocity = 3.0 x 10⁶ m/s
So,
t = 3.67 x 10⁻⁸ sec
Now calculate for vertical acceleration,
[tex]Y = v^o\times t + (0.5) a t^2[/tex]
Where,
Y - verical distance = 34 cm = 0.34 m
v^o - initial vertical velocity = 0 m/s.
a - acceleration = ?
Put the values in the formula,
0.34 = (0) (3.67 x 10⁻⁸) + (0.5) a (3.67 x 10⁻⁸)²
a = 5.05 x 10¹⁴ m/s²
Therefore, the vertical acceleration provided by the deflector is 5.05 x 10¹⁴ m/s².
Learn more about vertical acceleration :
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