Answer:
[tex]x_1=-6.9\\x_2=0.9[/tex]
Step-by-step explanation:
The first step is to move all the terms from the right side to the left side of the equation and then add the like terms:
[tex]2x^2+12x-16=-3\\\\2x^2+12x-16+3=0\\\\2x^2+12x-13=0[/tex]
Now we can apply the Quadratic formula. This is:
[tex]x=\frac{-b\±\sqrt{b^2-4ac}}{2a}[/tex]
In this case we can identify that:
[tex]a=2\\b=12\\c=-13[/tex]
Finally, we must substitute these values into the Quadratic formula. Then we get:
[tex]x=\frac{-12\±\sqrt{((12)^2-4(2)(-13)}}{2(2)}[/tex]
[tex]x_1=-6.9\\x_2=0.9[/tex]
