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A heat engine having the maximum possible efficiency has an efficiency of 0.35 when operating between two heat reservoirs. If the temperature of the hot reservoir is 427°C, what is the temperature of the cold reservoir? (5 pts) A) 200 K B) 245 K C) 350 K D) 455 K E) 600 K

Respuesta :

Answer:

Option (D)

Explanation:

n = 0.35,

Temperature of hot reservoir,

T1 = 427 C = 700 K

Temperature of cold reservoir, T2 = ?

Use the formula for efficiency of Carnot cycle

n = 1 - T2 / T1

0.35 = 1 - T2 / 700

0.65 = T2 / 700

T2 = 700 × 0.65

T2 = 455 K

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