(a) The impulse delivered to the ball by the racket is 5.24 kg.m/s
(b) The work that the racket does on the ball is -35.1 Joule
Further Explanation
Given :
mass of ball = m = 0.06 kg
initial velocity = v₁ = -50.4 m/s
final velocity = v₂ = 37.0 m/s
Unknown :
(a) Impulse = I = ?
(b) Work = W = ?
Solution :
Question (a) :
In this question , we could use the formula from Second Law of Newton :
[tex]I = \Delta p[/tex]
[tex]I = p_2 - p_1[/tex]
[tex]I = m \times v_2 - m \times v_1[/tex]
[tex]I = m \times (v_2 - v_1)[/tex]
[tex]I = 0.06 \times (37.0 - (-50.4))[/tex]
[tex]I = 0.06 \times (87.4)[/tex]
[tex]I = 5.244~kg.m/s[/tex]
[tex]\large { \boxed {I \approx 5.24~kg.m/s} }[/tex]
Question (b) :
[tex]W = F \times d[/tex]
[tex]W = (\frac{I}{\Delta t})(\frac {v_1 + v_2}{2} \Delta t)[/tex]
[tex]W = \frac{I(v_1 + v_2)}{2}[/tex]
[tex]W = \frac{5.244(-50.4 + 37)}{2}[/tex]
[tex]W = \frac{5.244(-13.4)}{2}[/tex]
[tex]W = -35.1348~Joule[/tex]
[tex]\large { \boxed {W \approx -35.1~Joule}}[/tex]
Learn more
Newton's Law of Motion: https://brainly.com/question/10431582
Example of Newton's Law: https://brainly.com/question/498822
Answer details
Grade: High School
Subject: Physics
Chapter: Dynamics
Keywords: Newton, Law, Impulse, Work
