Respuesta :

Answer:

The equation of tangent line is [tex]y=5x-33  [/tex]

Step-by-step explanation:

We need to find out the equation of tangent line.

Given :- g(6)=−3  and  g'(6)=  5

If  g(6)=−3

then the point on the line for the required tangent is  (6,−3)

If  g'(6)=  5

then the slope of the tangent at that point is  45

The tangent line can be specified by the slope-point form of the equation:

[tex](y-y_1)=m(x-x_1)[/tex]

which in this case is

[tex](y-(-3))=5(x-6)[/tex]

[tex](y+3)=(5x-30)[/tex]

subtract both the sides by 3,

[tex]y+3-3=5x-30-3[/tex]

[tex]y=5x-33[/tex]

Therefore, the equation of tangent line is [tex]y=5x-33[/tex]