Answer:
The equation of tangent line is [tex]y=5x-33 [/tex]
Step-by-step explanation:
We need to find out the equation of tangent line.
Given :- g(6)=−3 and g'(6)= 5
If g(6)=−3
then the point on the line for the required tangent is (6,−3)
If g'(6)= 5
then the slope of the tangent at that point is 45
The tangent line can be specified by the slope-point form of the equation:
[tex](y-y_1)=m(x-x_1)[/tex]
which in this case is
[tex](y-(-3))=5(x-6)[/tex]
[tex](y+3)=(5x-30)[/tex]
subtract both the sides by 3,
[tex]y+3-3=5x-30-3[/tex]
[tex]y=5x-33[/tex]
Therefore, the equation of tangent line is [tex]y=5x-33[/tex]