Please help me with this please

always remember
[tex] \sqrt[i]{ {a}^{b} } = {a}^{ \frac{b}{i} } [/tex]
except in cases that <i> is even & b is less than zero, or A will have a negative power.
here you have:
[tex] {x}^{ \frac{1}{3} + \frac{5}{2} + 1 } \div {x}^{ \frac{1}{2} } [/tex]
and a simple job:
[tex] \frac{1}{3} + \frac{5}{2} + 1 - \frac{1}{2 } = \frac{1}{3 } + \frac{4}{2} + 1 = 3 + \frac{1}{3} [/tex]
finally answer is:
[tex] {x}^{ \frac{10}{3} } = {x}^{3} \sqrt[3]{x} [/tex]