Respuesta :

superman1987

Answer:

1.445 x 10²³ atoms.

Explanation:

  • It is known that 1.0 mole of any element contains Avogadro's no. (6.022 x 10²³) of atoms.

Using cross multiplication:

1 mol of Ag contains → 6.022 x 10²³ atoms.

∴ 0.24 mol of Ag contains → ??? atoms.

∴ The no. of Ag atoms in 0.24 mol = (0.24 mol)(6.022 x 10²³ atoms)/(1 mol) = 1.445 x 10²³ atoms.

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