Respuesta :

gmany

Answer:

[tex]\large\boxed{15\div6\dfrac{2}{3}=2\dfrac{1}{4}}[/tex]

Step-by-step explanation:

[tex]15\div6\dfrac{2}{3}\\\\\text{convert the mixed number to the improper fraction:}\ 6\dfrac{2}{3}=\dfrac{6\cdot3+2}{3}=\dfrac{20}{3}\\\\15\div\dfrac{20}{3}=15\cdot\dfrac{3}{20}=15\!\!\!\!\!\diagup^3\cdot\dfrac{3}{20\!\!\!\!\!\diagup_4}=\dfrac{(3)(3)}{4}=\dfrac{9}{4}=2\dfrac{1}{4}[/tex]

carlosego

For this case we must rewrite the mixed number as a fraction:

[tex]6 \frac {2} {3} = \frac {3 * 6 + 2} {3} = \frac {20} {3}[/tex]

Rewriting the expression we have:

[tex]\frac {\frac {15} {1}} {\frac {20} {3}} =[/tex]

Applying double C we have:

[tex]\frac {3 * 15} {20 * 1} =\\\frac {45} {20} =[/tex]

We simplify dividing by 5 the numerator and denominator:

[tex]\frac {9} {4}[/tex]

Converting to mixed number we have:

[tex]2 \frac {1} {4}[/tex]

Answer:

[tex]\frac {9} {4} = 2 \frac {1} {4}[/tex]

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