Answer:
The new sequence
-40, -160, -640, -2560, -10240, -40960
Step-by-step explanation:
It is given that,
aₙ = 4a₍ₙ₋₁₎ and a₁ = -10
To find the first 7 terms of the sequence
a₁ = -10
a₂ = 4a₁ = 4 * (-10) = -40
a₃ = 4a₂ = 4 * (-40) = -160
a₄ = 4a₃ = 4 * ( -160) = -640
a₅ = 4a₄ = 4 * (-640) = -2560
a₆ = 4a₅ = 4 * (-2560) = -10240
a₇ = 4a₆ = 4 * (-10240) = -40960
Therefore the new sequence
-40, -160, -640, -2560, -10240, -40960
Answer:Given Below
Step-by-step explanation:
Given
[tex]a_1=-10[/tex]
[tex]a_n=4a_{n-1}[/tex] for n greater than equal to 2
using above equation
[tex]a_2=4a_1=4(-10)=-40[/tex]
[tex]a_3=4a_2=4(-40)=-160[/tex]
[tex]a_4=4a_3=4(-160)=-640 [/tex]
[tex]a_5=4a_4=4(-640)=-2560[/tex]
[tex]a_6=4a_5=4(-2560)=-10,240 [/tex]
