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i will give brainliest A whole number is 6 more than 2 times another number. The sum of the two numbers is less than 50. This can be written in an inequality as x + 2x + 6 < 50, where x represents the smaller number.
From the set {13, 14, 15, 16, 17}, the values of x for which the inequality holds true are .

Respuesta :

Answer:

13 and 14

Step-by-step explanation:

13+ (2*13) +6= 45 which is less than 50

14+ (2*14) +6= 48 which is also less than 50.

When you do the same with 15,16, and 17 the answers all come out to be  51, 54, and 57 which are all greater than 50

Answer:

13 and 14

Step-by-step explanation:

Given : [tex]x + 2x + 6 < 50[/tex]

To Find : From the set {13, 14, 15, 16, 17}, the values of x for which the inequality holds true are .

Solution:

Inequality :  [tex]x + 2x + 6 < 50[/tex]

Substitute x =  13

[tex]13 + 2(13) + 6 < 50[/tex]

[tex]45 < 50[/tex]

Substitute x = 14

[tex]14 + 2(14) + 6 < 50[/tex]

[tex]48 < 50[/tex]

Substitute x = 15

[tex]15 + 2(15) + 6 < 50[/tex]

[tex]51 > 50[/tex]

Substitute x = 16

[tex]16+ 2(16) + 6 < 50[/tex]

[tex]54 > 50[/tex]

Substitute x = 17

[tex]17+ 2(17) + 6 < 50[/tex]

[tex]57 > 50[/tex]

So,  the values of x for which the inequality holds true are 13 and 14.

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