Aaron invested $4000 in an account that paid an interest rate r compounded quarterly. After 10 years he has $5809.81. The compound interest formula is A=P (1 +r/n)^nt, where P is the principal (the initial investment), A is the total amount of money (principal plus interest), r is the annual interest rate, t is the time in years, and n is the number of compounding periods per year.

a. Divide both sides of the formula by P and then use logarithms to rewrite the formula without an exponent. Show your work.

b. Using your answer for part a as a starting point, solve the compound interest formula for the interest rate, r.

c. Use your equation from part a to determine the interest rate.

Respuesta :

Answer:A

Step-by-step explanation:

Answer:

3.73%

Step-by-step explanation:

The formula is

[tex]A=P(1+\frac{r}{n})^{tn}[/tex]

Here we are given that A= 5809.81 , P=4000 , t=10 years and n = 4 (compounded quaterly)

Now we have to substitute them in the formula

[tex]5809.81=4000(1+\frac{r}{4})^{40}[/tex]

[tex]\frac{5809.81}{4000}=(1+\frac{r}{4})^{40}[/tex]

[tex] (\frac{5809.81}{4000})^{\frac{1}{40}}=1+\frac{r}{4}[/tex]

[tex] (1.45)^{\frac{1}{40}}=1+\frac{r}{4}[/tex]

[tex]1.0093 = 1+\frac{r}{4}[/tex]

Subtracting 1 on both sides

[tex]0.0093=\frac{r}{4}[/tex]

[tex]r=0.0093*4[/tex]

r=0.03732

Rate is 3.73%

Otras preguntas