An artist is creating a large painting from a photograph by dividing the photograph into squares and dilating each square by a factor of 4. If the photograph is 4 in. by 6in., what is the perimeter of the painting? HELP ASAP!!

80 in.
384 in.
28 in.

Respuesta :

Answer:

  80 in.

Step-by-step explanation:

The dimensions of the dilated picture are ...

  4·4 in = 16 in . . . by . . . 4·6 in = 24 in

Then the perimeter of the painting is the sum of the lengths of its sides ...

  16 in + 24 in + 16 in + 24 in = 80 in

Answer:

80in

Step-by-step explanation:

The scale factor of the dilation is 4, so a 1 inch by 1 inch square on the photograph represents a 4 inch by 4

inch square on the painting.

The height of the image is the product of the height of the preimage and the scale factor.

w=4(6)=24

in

.

The width of the image is the product of the width of the preimage and the scale factor.

h=4(4)=16

in

.

So, the perimeter is

P=2(16)+2(24)=80

in

.

The figure shows two rectangles. The larger rectangle is 16 inches long and 24 inches wide. The smaller rectangle is 4 inches long and 6 inches wide. The sides of the larger rectangle are parallel to the corresponding sides of the smaller one, respectively.

Therefore, the perimeter of the painting is 80

inches.