Answer:
So there are 35 quarters and 21 nickels.
Step-by-step explanation:
So I guess that is all we have is quarters and nickels.
Quarters are worth .25
Nickels are worth .05
Let x represent the number of quarters
Let y represent the number of nickels
x+y=56
.25x+.05y=9.8
We are going to solve this system.
I'm going to use substitution. I will solve the first equation for y and then plug that into the second equation.
y=56-x
.25x+.05(56-x)=9.8
.25x+2.8-.05x=9.8
.20x+2.8=9.8
.2x = 7
x=7/(.2) or 7*5=35
y=56-x
y=56-35=21
So there are 35 quarters and 21 nickels.
Answer:
A) n + q = 56
B) .05n + .25q = 9.80
We multiply A) by -.25
A) -.25n -.25q = -14 then add it to equation B)
B) .05n + .25q = 9.80
-.2n = -4.20
nickels = 4.20 / .20 = 21
quarters = 35
Step-by-step explanation:
