Answer:
The number of protons 6.19 more than electron.
Explanation:
Given that,
Charge [tex]Q=+9.9\times10^{-6}\ C[/tex]
We know that,
formula of charge
[tex]Q = nc[/tex]
Where,
Q = total charge
n = number of protons
e = charge of electron
Put the value into the formula
[tex]n = \dfrac{Q}{e}[/tex]
[tex]n=\dfrac{9.9\times10^{-6}}{1.6\times10^{-19}}[/tex]
[tex]n=6.1875\times10^{13}\ C[/tex]
According to statement of question
Divide the answer by [tex]10^{13}[/tex]
[tex]n=\dfrac{6.1875\times10^{13}}{10^{13}}[/tex]
[tex]n=6.19\ C[/tex]
Hence, The number of protons 6.19 more than electron.
