What transformation were applied to ABCD to obtain A’B’C’D?

Answer:
Rotation 90 degree counterclockwise then 2 units up.
Step-by-step explanation:
Given : Quadrilateral ABCD and A'B'C'D'.
To find: What transformation were applied to ABCD to obtain A’B’C’D.
Solution: We have given
A (3,6) →→ A'(-6,5)
B( 3,9)→→ B'(-9 ,5)
C(7,9)→→C'(-9 ,9)
D(7,6)→→D'(-6,9)
By the 90 degree rotational rule : (x ,y) →→(-y ,x) and unit 2 unit up
A (3,6) →→ A'(-6,3) →→ A'(-6,3+2)
B( 3,9)→→ B'(-9 ,3)→→ B'(-9 ,3+2)
C(7,9)→→C'(-9 ,7) →→C'(-9 ,7+2)
D(7,6)→→D'(-6,7)→→D'(-6,7+2)
Therefore, Rotation 90 degree counterclockwise then 2 units up.
The transformation applied is Rotation 90 degree counterclockwise then 2 units up.
A coordinate system in geometry is a system that employs one or more integers, or coordinates, to define the position of points or other geometric components on a manifold such as Euclidean space.
The transformation which was applied to ABCD to obtain A’B’C’D be found by finding the change in the coordinates of the quadrilateral. Therefore,
As it is observed that the change in the coordinate is 90 degrees counterclockwise then 2 units up. Therefore, the transform of the coordinates can be done as (x ,y)⇒(-y ,x)⇒(-y, x+2).
Since the condition holds true, it can be concluded that the transformation applied is Rotation 90 degree counterclockwise then 2 units up.
Learn more about Coordinates:
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